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A necessary condition for an interior optimum

From your previous study of mathematics, you probably know that if the function  f  is differentiable there is a relationship between the solutions of the problem
maxx f (x) subject to x Î [a,b].
and the points at which the first derivative of  f  is zero---the stationary points of  f . What precisely is this relationship?

Consider the cases in the three figures.

We see that That is, being a stationary point is neither a necessary condition nor a sufficient condition for solving the problem. So what is the relation between stationary points and maximizers?

Although a maximizer may not be a stationary point, the only case in which it is not is when it is one of the endpoints of the interval [a,b] on which  f  is defined. That is, any point interior to this interval that is a maximum must be a stationary point.

Proposition
Let  f  be a differentiable function of a single variable defined on the interval [ab]. If x Î (ab) is a local or global maximizer or minimizer of  f  then  f ¢(x) = 0.

This result gives a necessary condition for x to be a maximizer (or a minimizer) of  f : if it is a maximizer (or a minimizer) and is between a and b then x is a stationary point of  f . The condition is obvously not sufficient for a point to be a maximizer---the condition is satisfied also, for example, at points that are minimizers. Since the first-derivative is involved, we refer to it as a first-order condition.

Thus among all the points in the interval [a,b], only a, b, and the stationary points of  f  can possibly be maximizers of  f . Since most functions have a relatively small number of stationary points, a reasonable way of finding maximizers is the following:

Exercise
Copyright © 1997 by Martin J. Osborne